(x-4)(x+5)=x^2-7x+17

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Solution for (x-4)(x+5)=x^2-7x+17 equation: 



(x-4)(x+5)=x^2-7x+17

We move all terms to the left:

(x-4)(x+5)-(x^2-7x+17)=0

We get rid of parentheses

-x^2+(x-4)(x+5)+7x-17=0

We multiply parentheses ..

-x^2+(+x^2+5x-4x-20)+7x-17=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+5x-4x-20)+7x-17=0

We get rid of parentheses

-1x^2+x^2+5x-4x+7x-20-17=0

We add all the numbers together, and all the variables

8x-37=0

We move all terms containing x to the left, all other terms to the right

8x=37

x=37/8

x=4+5/8

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